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Post by 1 on Dec 4, 2008 2:44:16 GMT -5
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Post by Daryl on Dec 4, 2008 14:20:11 GMT -5
Doesn't look so hard. Wouldn't the same principles people use to solve the 3x3x3 model apply?
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Post by 1 on Dec 4, 2008 17:17:41 GMT -5
I don't know the principals, so, I am not sure.
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Post by hellomeow on Dec 5, 2008 17:17:31 GMT -5
Obviously not. As you increase the amount of units in a Rubik's Cube the amount of algorithms needed to be applied in order to solve it increase too, and completely different problems arise in solving it. Saying that solving a 3x3x3 Rubik's Cube is the same as solving a 7x7x7 Rubik's Cube might as well be the same as saying that finding a general solution for ax^3+bx^2+cx+d=0 is the same as finding a general solution for ax^7+bx^6+cx^5+dx^4+ex^3+fx^2+gx+h=0.
Also I need to get one of those. I would say that one of my goals in life is being able to solve the V-Cube 7 in under 10 minutes as many other current speedcubists have.
When the advent of the V-Cube 8 comes along I will solve that too, however I haven't found so much as a V-Cube 5 or a Professor's Cube for some time :/
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Post by hellomeow on Dec 24, 2008 22:50:39 GMT -5
rofl principals.
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