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Post by Cheesemaster IV on Oct 7, 2009 0:21:59 GMT -5
Inspired by the following conversation, I have come up with a challenge.
If we assign a value to each letter of the alphabet, so that A = 1, B = 2, C = 3 ... Z = 26, and add up all the letter values in a word, we can get a value for a word.
For example, MICHAEL = 13 + 9 + 3 + 8 + 5 + 12 = 50 and KALSI = 11 + 1 + 12 + 19 + 9 = 52.
The sum of all the letter values in my middle name is 58.
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Ishtari
Passing By
aw i sorry
Posts: 71
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Post by Ishtari on Nov 5, 2012 19:01:13 GMT -5
Way not to add the value of A in MICHAEL.
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Post by Hauskaz on Nov 5, 2012 19:15:07 GMT -5
I did make a program to solve this, but the problem was sorting out possible names out of the giant list of incoherency it generated.
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Post by Cheesemaster V on Nov 5, 2012 19:42:32 GMT -5
I think I disposed of this competition when I later realized my hint still left you with an absurd number of combinations (# of compositions of 58 with no parts larger than 26 = 144,115,188,075,855,872 - some number much smaller than that = some still ridiculously high number of combinations).
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Ishtari
Passing By
aw i sorry
Posts: 71
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Post by Ishtari on Nov 5, 2012 19:43:03 GMT -5
It's too bad the WatIAM White Pages aren't part of Waterloo's Open Data API. But that would clearly be cheating anyway.
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Post by Mr Momentum & the Sidesteppers on Nov 19, 2012 11:50:59 GMT -5
well this thread has been silked because we all know his name is Mandeep and it adds up to 58.
I just remember seeing a question with Kalsi's name on it on one of the CS mailing lists and laughing for 5 minutes because his middle name was Mandeep.
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